12(v+4)-4v=2(4v+1)-5

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Solution for 12(v+4)-4v=2(4v+1)-5 equation: 



12(v+4)-4v=2(4v+1)-5

We move all terms to the left:

12(v+4)-4v-(2(4v+1)-5)=0

We add all the numbers together, and all the variables

-4v+12(v+4)-(2(4v+1)-5)=0

We multiply parentheses

-4v+12v-(2(4v+1)-5)+48=0



We calculate terms in parentheses: -(2(4v+1)-5), so:

2(4v+1)-5

We multiply parentheses

8v+2-5

We add all the numbers together, and all the variables

8v-3

Back to the equation:

-(8v-3)



We add all the numbers together, and all the variables

8v-(8v-3)+48=0

We get rid of parentheses

8v-8v+3+48=0

We add all the numbers together, and all the variables

51!=0

There is no solution for this equation

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