12(v+4)-4v=4(2v+2)-13

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Solution for 12(v+4)-4v=4(2v+2)-13 equation: 


Simplifying
12(v + 4) + -4v = 4(2v + 2) + -13

Reorder the terms:
12(4 + v) + -4v = 4(2v + 2) + -13
(4 * 12 + v * 12) + -4v = 4(2v + 2) + -13
(48 + 12v) + -4v = 4(2v + 2) + -13

Combine like terms: 12v + -4v = 8v
48 + 8v = 4(2v + 2) + -13

Reorder the terms:
48 + 8v = 4(2 + 2v) + -13
48 + 8v = (2 * 4 + 2v * 4) + -13
48 + 8v = (8 + 8v) + -13

Reorder the terms:
48 + 8v = 8 + -13 + 8v

Combine like terms: 8 + -13 = -5
48 + 8v = -5 + 8v

Add '-8v' to each side of the equation.
48 + 8v + -8v = -5 + 8v + -8v

Combine like terms: 8v + -8v = 0
48 + 0 = -5 + 8v + -8v
48 = -5 + 8v + -8v

Combine like terms: 8v + -8v = 0
48 = -5 + 0
48 = -5

Solving
48 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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