12(v+4)-4v=4(2v+4)-22

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Solution for 12(v+4)-4v=4(2v+4)-22 equation:


Simplifying
12(v + 4) + -4v = 4(2v + 4) + -22

Reorder the terms:
12(4 + v) + -4v = 4(2v + 4) + -22
(4 * 12 + v * 12) + -4v = 4(2v + 4) + -22
(48 + 12v) + -4v = 4(2v + 4) + -22

Combine like terms: 12v + -4v = 8v
48 + 8v = 4(2v + 4) + -22

Reorder the terms:
48 + 8v = 4(4 + 2v) + -22
48 + 8v = (4 * 4 + 2v * 4) + -22
48 + 8v = (16 + 8v) + -22

Reorder the terms:
48 + 8v = 16 + -22 + 8v

Combine like terms: 16 + -22 = -6
48 + 8v = -6 + 8v

Add '-8v' to each side of the equation.
48 + 8v + -8v = -6 + 8v + -8v

Combine like terms: 8v + -8v = 0
48 + 0 = -6 + 8v + -8v
48 = -6 + 8v + -8v

Combine like terms: 8v + -8v = 0
48 = -6 + 0
48 = -6

Solving
48 = -6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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