12(x+1)=2(6x-5)+22

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Solution for 12(x+1)=2(6x-5)+22 equation: 



12(x+1)=2(6x-5)+22

We move all terms to the left:

12(x+1)-(2(6x-5)+22)=0

We multiply parentheses

12x-(2(6x-5)+22)+12=0



We calculate terms in parentheses: -(2(6x-5)+22), so:

2(6x-5)+22

We multiply parentheses

12x-10+22

We add all the numbers together, and all the variables

12x+12

Back to the equation:

-(12x+12)



We get rid of parentheses

12x-12x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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