12(x+1)=32(3x-2)

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Solution for 12(x+1)=32(3x-2) equation: 



12(x+1)=32(3x-2)

We move all terms to the left:

12(x+1)-(32(3x-2))=0

We multiply parentheses

12x-(32(3x-2))+12=0



We calculate terms in parentheses: -(32(3x-2)), so:

32(3x-2)

We multiply parentheses

96x-64

Back to the equation:

-(96x-64)



We get rid of parentheses

12x-96x+64+12=0

We add all the numbers together, and all the variables

-84x+76=0

We move all terms containing x to the left, all other terms to the right

-84x=-76

x=-76/-84

x=19/21

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