12(x+1)=4(3x+1)+8

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Solution for 12(x+1)=4(3x+1)+8 equation: 


Simplifying
12(x + 1) = 4(3x + 1) + 8

Reorder the terms:
12(1 + x) = 4(3x + 1) + 8
(1 * 12 + x * 12) = 4(3x + 1) + 8
(12 + 12x) = 4(3x + 1) + 8

Reorder the terms:
12 + 12x = 4(1 + 3x) + 8
12 + 12x = (1 * 4 + 3x * 4) + 8
12 + 12x = (4 + 12x) + 8

Reorder the terms:
12 + 12x = 4 + 8 + 12x

Combine like terms: 4 + 8 = 12
12 + 12x = 12 + 12x

Add '-12' to each side of the equation.
12 + -12 + 12x = 12 + -12 + 12x

Combine like terms: 12 + -12 = 0
0 + 12x = 12 + -12 + 12x
12x = 12 + -12 + 12x

Combine like terms: 12 + -12 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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