12(x+2)-7=7(3x-4)

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Solution for 12(x+2)-7=7(3x-4) equation: 



12(x+2)-7=7(3x-4)

We move all terms to the left:

12(x+2)-7-(7(3x-4))=0

We multiply parentheses

12x-(7(3x-4))+24-7=0



We calculate terms in parentheses: -(7(3x-4)), so:

7(3x-4)

We multiply parentheses

21x-28

Back to the equation:

-(21x-28)



We add all the numbers together, and all the variables

12x-(21x-28)+17=0

We get rid of parentheses

12x-21x+28+17=0

We add all the numbers together, and all the variables

-9x+45=0

We move all terms containing x to the left, all other terms to the right

-9x=-45

x=-45/-9

x=+5

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