12(x+3)+6=2(x-2)

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Solution for 12(x+3)+6=2(x-2) equation: 



12(x+3)+6=2(x-2)

We move all terms to the left:

12(x+3)+6-(2(x-2))=0

We multiply parentheses

12x-(2(x-2))+36+6=0



We calculate terms in parentheses: -(2(x-2)), so:

2(x-2)

We multiply parentheses

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

12x-(2x-4)+42=0

We get rid of parentheses

12x-2x+4+42=0

We add all the numbers together, and all the variables

10x+46=0

We move all terms containing x to the left, all other terms to the right

10x=-46

x=-46/10

x=-4+3/5

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