12(x+3)-20=64

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Solution for 12(x+3)-20=64 equation: 



12(x+3)-20=64

We move all terms to the left:

12(x+3)-20-(64)=0

We add all the numbers together, and all the variables

12(x+3)-84=0

We multiply parentheses

12x+36-84=0

We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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