12(x+3)=4(3x+1)+32

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Solution for 12(x+3)=4(3x+1)+32 equation: 


Simplifying
12(x + 3) = 4(3x + 1) + 32

Reorder the terms:
12(3 + x) = 4(3x + 1) + 32
(3 * 12 + x * 12) = 4(3x + 1) + 32
(36 + 12x) = 4(3x + 1) + 32

Reorder the terms:
36 + 12x = 4(1 + 3x) + 32
36 + 12x = (1 * 4 + 3x * 4) + 32
36 + 12x = (4 + 12x) + 32

Reorder the terms:
36 + 12x = 4 + 32 + 12x

Combine like terms: 4 + 32 = 36
36 + 12x = 36 + 12x

Add '-36' to each side of the equation.
36 + -36 + 12x = 36 + -36 + 12x

Combine like terms: 36 + -36 = 0
0 + 12x = 36 + -36 + 12x
12x = 36 + -36 + 12x

Combine like terms: 36 + -36 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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