12(x+3)=4x-4(x+3)

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Solution for 12(x+3)=4x-4(x+3) equation: 



12(x+3)=4x-4(x+3)

We move all terms to the left:

12(x+3)-(4x-4(x+3))=0

We multiply parentheses

12x-(4x-4(x+3))+36=0



We calculate terms in parentheses: -(4x-4(x+3)), so:

4x-4(x+3)

We multiply parentheses

4x-4x-12

We add all the numbers together, and all the variables

-12

Back to the equation:

-(-12)



We add all the numbers together, and all the variables

12x+48=0

We move all terms containing x to the left, all other terms to the right

12x=-48

x=-48/12

x=-4

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