12(x+3)=6(2x+4)+12

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Solution for 12(x+3)=6(2x+4)+12 equation: 



12(x+3)=6(2x+4)+12

We move all terms to the left:

12(x+3)-(6(2x+4)+12)=0

We multiply parentheses

12x-(6(2x+4)+12)+36=0



We calculate terms in parentheses: -(6(2x+4)+12), so:

6(2x+4)+12

We multiply parentheses

12x+24+12

We add all the numbers together, and all the variables

12x+36

Back to the equation:

-(12x+36)



We get rid of parentheses

12x-12x-36+36=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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