12(x+3)=6(4+3x)

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Solution for 12(x+3)=6(4+3x) equation: 



12(x+3)=6(4+3x)

We move all terms to the left:

12(x+3)-(6(4+3x))=0

We add all the numbers together, and all the variables

12(x+3)-(6(3x+4))=0

We multiply parentheses

12x-(6(3x+4))+36=0



We calculate terms in parentheses: -(6(3x+4)), so:

6(3x+4)

We multiply parentheses

18x+24

Back to the equation:

-(18x+24)



We get rid of parentheses

12x-18x-24+36=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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