12(x+4)=4(3x+2)+40

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Solution for 12(x+4)=4(3x+2)+40 equation:


Simplifying
12(x + 4) = 4(3x + 2) + 40

Reorder the terms:
12(4 + x) = 4(3x + 2) + 40
(4 * 12 + x * 12) = 4(3x + 2) + 40
(48 + 12x) = 4(3x + 2) + 40

Reorder the terms:
48 + 12x = 4(2 + 3x) + 40
48 + 12x = (2 * 4 + 3x * 4) + 40
48 + 12x = (8 + 12x) + 40

Reorder the terms:
48 + 12x = 8 + 40 + 12x

Combine like terms: 8 + 40 = 48
48 + 12x = 48 + 12x

Add '-48' to each side of the equation.
48 + -48 + 12x = 48 + -48 + 12x

Combine like terms: 48 + -48 = 0
0 + 12x = 48 + -48 + 12x
12x = 48 + -48 + 12x

Combine like terms: 48 + -48 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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