12(x+5)-2/3(6-24x)=3/4(-8x-12)

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Solution for 12(x+5)-2/3(6-24x)=3/4(-8x-12) equation: 



12(x+5)-2/3(6-24x)=3/4(-8x-12)

We move all terms to the left:

12(x+5)-2/3(6-24x)-(3/4(-8x-12))=0



Domain of the equation: 3(6-24x)!=0

x∈R





Domain of the equation: 4(-8x-12))!=0

x∈R



We add all the numbers together, and all the variables

12(x+5)-2/3(-24x+6)-(3/4(-8x-12))=0

We multiply parentheses

12x-2/3(-24x+6)-(3/4(-8x-12))+60=0

We calculate fractions


12x+(-8x(-)/(3(-24x+6)*4(-8x-12)))+(-9x0/(3(-24x+6)*4(-8x-12)))+60=0



We calculate terms in parentheses: +(-8x(-)/(3(-24x+6)*4(-8x-12))), so:

-8x(-)/(3(-24x+6)*4(-8x-12))

We add all the numbers together, and all the variables

-8x0/(3(-24x+6)*4(-8x-12))

We multiply all the terms by the denominator


-8x0

We add all the numbers together, and all the variables

-8x

Back to the equation:

+(-8x)





We calculate terms in parentheses: +(-9x0/(3(-24x+6)*4(-8x-12))), so:

-9x0/(3(-24x+6)*4(-8x-12))

We multiply all the terms by the denominator


-9x0

We add all the numbers together, and all the variables

-9x

Back to the equation:

+(-9x)



We get rid of parentheses

12x-8x-9x+60=0

We add all the numbers together, and all the variables

-5x+60=0

We move all terms containing x to the left, all other terms to the right

-5x=-60

x=-60/-5

x=+12

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