12(x+5)=19+3x

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Solution for 12(x+5)=19+3x equation: 



12(x+5)=19+3x

We move all terms to the left:

12(x+5)-(19+3x)=0

We add all the numbers together, and all the variables

12(x+5)-(3x+19)=0

We multiply parentheses

12x-(3x+19)+60=0

We get rid of parentheses

12x-3x-19+60=0

We add all the numbers together, and all the variables

9x+41=0

We move all terms containing x to the left, all other terms to the right

9x=-41

x=-41/9

x=-4+5/9

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