12(x+9)-40=10x+68

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Solution for 12(x+9)-40=10x+68 equation: 



12(x+9)-40=10x+68

We move all terms to the left:

12(x+9)-40-(10x+68)=0

We multiply parentheses

12x-(10x+68)+108-40=0

We get rid of parentheses

12x-10x-68+108-40=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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