12(x-1)=2(6x+3)-18

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Solution for 12(x-1)=2(6x+3)-18 equation:



12(x-1)=2(6x+3)-18
We move all terms to the left:
12(x-1)-(2(6x+3)-18)=0
We multiply parentheses
12x-(2(6x+3)-18)-12=0
We calculate terms in parentheses: -(2(6x+3)-18), so:
2(6x+3)-18
We multiply parentheses
12x+6-18
We add all the numbers together, and all the variables
12x-12
Back to the equation:
-(12x-12)
We get rid of parentheses
12x-12x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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