12(x-1)=2(6x+3)-18

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Solution for 12(x-1)=2(6x+3)-18 equation: 



12(x-1)=2(6x+3)-18

We move all terms to the left:

12(x-1)-(2(6x+3)-18)=0

We multiply parentheses

12x-(2(6x+3)-18)-12=0



We calculate terms in parentheses: -(2(6x+3)-18), so:

2(6x+3)-18

We multiply parentheses

12x+6-18

We add all the numbers together, and all the variables

12x-12

Back to the equation:

-(12x-12)



We get rid of parentheses

12x-12x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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