If it's not what You are looking for type in the equation solver your own equation and let us solve it.
12(x-1)=4(2x-3)
We move all terms to the left:
12(x-1)-(4(2x-3))=0
We multiply parentheses
12x-(4(2x-3))-12=0
We calculate terms in parentheses: -(4(2x-3)), so:We get rid of parentheses
4(2x-3)
We multiply parentheses
8x-12
Back to the equation:
-(8x-12)
12x-8x+12-12=0
We add all the numbers together, and all the variables
4x=0
x=0/4
x=0
| 80+50+65+x=180 | | 30=16t^2+24t+30 | | 5t^2+30t-80=0 | | 43+57+x+x=x | | 4x+24=13x-7 | | 2/5=1/2c | | 8t+1=3t-1 | | 17-16g=-17g+14 | | 6f=-4+2f | | 3.6x+1.2=4.8;x=1 | | -7+5v=5v-10 | | 3c+c+3=19 | | x-2/x-4=-2/x-1 | | 21x-21x=0 | | 5y-6=5y+9 | | -2m-10-10m=-10+10 | | 12/|x|-6,06=-0,06 | | -9h-1=-9h+8 | | 3a^2=-19+18a | | 3(−2x+4)=2x−4 | | -10+2g=10-2g | | 6x-9=9x+2 | | -1-7n=-8n | | 3x+7x+1(x-5)=5 | | 6x6=24 | | 1-x^2=50 | | 8b+6=-4+7b | | 4/x+2=6/x-2 | | 180=2x+(x+3) | | -10+8j+11j=20j-14 | | 4t+25=-3t-28 | | k^2+4=44 |