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12(x-2)+3x=(1/3)(x+6)+2
We move all terms to the left:
12(x-2)+3x-((1/3)(x+6)+2)=0
Domain of the equation: 3)(x+6)+2)!=0We add all the numbers together, and all the variables
x∈R
12(x-2)+3x-((+1/3)(x+6)+2)=0
We add all the numbers together, and all the variables
3x+12(x-2)-((+1/3)(x+6)+2)=0
We multiply parentheses
3x+12x-((+1/3)(x+6)+2)-24=0
We multiply parentheses ..
-((+x^2+1/3*6)+2)+3x+12x-24=0
We multiply all the terms by the denominator
-((+x^2+1+3x*3*6)+2)+12x*3*6)+2)-24*3*6)+2)=0
We calculate terms in parentheses: -((+x^2+1+3x*3*6)+2), so:Wy multiply elements
(+x^2+1+3x*3*6)+2
We get rid of parentheses
x^2+3x*3*6+1+2
We add all the numbers together, and all the variables
x^2+3x*3*6+3
Wy multiply elements
x^2+54x*6+3
Wy multiply elements
x^2+324x+3
Back to the equation:
-(x^2+324x+3)
3888x^3*6-(x^2+324x+3)=0
We get rid of parentheses
3888x^3*6-x^2-324x-3=0
We do not support expression: x^3
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