12(x-2)+3x=1/3(x+12)+10

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Solution for 12(x-2)+3x=1/3(x+12)+10 equation: 



12(x-2)+3x=1/3(x+12)+10

We move all terms to the left:

12(x-2)+3x-(1/3(x+12)+10)=0



Domain of the equation: 3(x+12)+10)!=0

x∈R



We add all the numbers together, and all the variables

3x+12(x-2)-(1/3(x+12)+10)=0

We multiply parentheses

3x+12x-(1/3(x+12)+10)-24=0

We multiply all the terms by the denominator


3x*3(x+12)+10)+12x*3(x+12)+10)-(1-24*3(x+12)+10)=0

We add all the numbers together, and all the variables

3x*3(x+12)+10)+12x*3(x+12)+10)-(1-24*3(x=0

Wy multiply elements

9x^2(x+10)+12x*3(x+12)-24*3(x+10)-(1=0

We add all the numbers together, and all the variables

9x^2(x+10)+12x*3(x+12)-24*3(x+10)=0

Wy multiply elements

9x^2(x+10)+36x^2(x-72x(x=0

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