12(x-2)=-3(1+3x)

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Solution for 12(x-2)=-3(1+3x) equation: 



12(x-2)=-3(1+3x)

We move all terms to the left:

12(x-2)-(-3(1+3x))=0

We add all the numbers together, and all the variables

12(x-2)-(-3(3x+1))=0

We multiply parentheses

12x-(-3(3x+1))-24=0



We calculate terms in parentheses: -(-3(3x+1)), so:

-3(3x+1)

We multiply parentheses

-9x-3

Back to the equation:

-(-9x-3)



We get rid of parentheses

12x+9x+3-24=0

We add all the numbers together, and all the variables

21x-21=0

We move all terms containing x to the left, all other terms to the right

21x=21

x=21/21

x=1

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