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12(x-2)=3(x+3)
We move all terms to the left:
12(x-2)-(3(x+3))=0
We multiply parentheses
12x-(3(x+3))-24=0
We calculate terms in parentheses: -(3(x+3)), so:We get rid of parentheses
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
12x-3x-9-24=0
We add all the numbers together, and all the variables
9x-33=0
We move all terms containing x to the left, all other terms to the right
9x=33
x=33/9
x=3+2/3
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