12(x-2)=4(1+8x)+8x

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Solution for 12(x-2)=4(1+8x)+8x equation: 



12(x-2)=4(1+8x)+8x

We move all terms to the left:

12(x-2)-(4(1+8x)+8x)=0

We add all the numbers together, and all the variables

12(x-2)-(4(8x+1)+8x)=0

We multiply parentheses

12x-(4(8x+1)+8x)-24=0



We calculate terms in parentheses: -(4(8x+1)+8x), so:

4(8x+1)+8x

We add all the numbers together, and all the variables

8x+4(8x+1)

We multiply parentheses

8x+32x+4

We add all the numbers together, and all the variables

40x+4

Back to the equation:

-(40x+4)



We get rid of parentheses

12x-40x-4-24=0

We add all the numbers together, and all the variables

-28x-28=0

We move all terms containing x to the left, all other terms to the right

-28x=28

x=28/-28

x=-1

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