12(x-3)+18=6(2x-3)

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Solution for 12(x-3)+18=6(2x-3) equation: 



12(x-3)+18=6(2x-3)

We move all terms to the left:

12(x-3)+18-(6(2x-3))=0

We multiply parentheses

12x-(6(2x-3))-36+18=0



We calculate terms in parentheses: -(6(2x-3)), so:

6(2x-3)

We multiply parentheses

12x-18

Back to the equation:

-(12x-18)



We add all the numbers together, and all the variables

12x-(12x-18)-18=0

We get rid of parentheses

12x-12x+18-18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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