12(x-3)+3(x-2)=18

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Solution for 12(x-3)+3(x-2)=18 equation: 



12(x-3)+3(x-2)=18

We move all terms to the left:

12(x-3)+3(x-2)-(18)=0

We multiply parentheses

12x+3x-36-6-18=0

We add all the numbers together, and all the variables

15x-60=0

We move all terms containing x to the left, all other terms to the right

15x=60

x=60/15

x=4

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