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12(x-3)+6=-3(x+5)
We move all terms to the left:
12(x-3)+6-(-3(x+5))=0
We multiply parentheses
12x-(-3(x+5))-36+6=0
We calculate terms in parentheses: -(-3(x+5)), so:We add all the numbers together, and all the variables
-3(x+5)
We multiply parentheses
-3x-15
Back to the equation:
-(-3x-15)
12x-(-3x-15)-30=0
We get rid of parentheses
12x+3x+15-30=0
We add all the numbers together, and all the variables
15x-15=0
We move all terms containing x to the left, all other terms to the right
15x=15
x=15/15
x=1
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