12(x-3)-(2x+1)=3(x+4)

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Solution for 12(x-3)-(2x+1)=3(x+4) equation: 



12(x-3)-(2x+1)=3(x+4)

We move all terms to the left:

12(x-3)-(2x+1)-(3(x+4))=0

We multiply parentheses

12x-(2x+1)-(3(x+4))-36=0

We get rid of parentheses

12x-2x-(3(x+4))-1-36=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

10x-(3x+12)-37=0

We get rid of parentheses

10x-3x-12-37=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7

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