12(x-3)-4=15x-64

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Solution for 12(x-3)-4=15x-64 equation: 



12(x-3)-4=15x-64

We move all terms to the left:

12(x-3)-4-(15x-64)=0

We multiply parentheses

12x-(15x-64)-36-4=0

We get rid of parentheses

12x-15x+64-36-4=0

We add all the numbers together, and all the variables

-3x+24=0

We move all terms containing x to the left, all other terms to the right

-3x=-24

x=-24/-3

x=+8

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