12(x-3)-8(x-3)=48-x

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Solution for 12(x-3)-8(x-3)=48-x equation: 



12(x-3)-8(x-3)=48-x

We move all terms to the left:

12(x-3)-8(x-3)-(48-x)=0

We add all the numbers together, and all the variables

12(x-3)-8(x-3)-(-1x+48)=0

We multiply parentheses

12x-8x-(-1x+48)-36+24=0

We get rid of parentheses

12x-8x+1x-48-36+24=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

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