12(x-3)=-2x-(96+8x)

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Solution for 12(x-3)=-2x-(96+8x) equation: 



12(x-3)=-2x-(96+8x)

We move all terms to the left:

12(x-3)-(-2x-(96+8x))=0

We add all the numbers together, and all the variables

12(x-3)-(-2x-(8x+96))=0

We multiply parentheses

12x-(-2x-(8x+96))-36=0



We calculate terms in parentheses: -(-2x-(8x+96)), so:

-2x-(8x+96)

We get rid of parentheses

-2x-8x-96

We add all the numbers together, and all the variables

-10x-96

Back to the equation:

-(-10x-96)



We get rid of parentheses

12x+10x+96-36=0

We add all the numbers together, and all the variables

22x+60=0

We move all terms containing x to the left, all other terms to the right

22x=-60

x=-60/22

x=-2+8/11

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