12(x-3)=2(6x+2)-40

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Solution for 12(x-3)=2(6x+2)-40 equation:


Simplifying
12(x + -3) = 2(6x + 2) + -40

Reorder the terms:
12(-3 + x) = 2(6x + 2) + -40
(-3 * 12 + x * 12) = 2(6x + 2) + -40
(-36 + 12x) = 2(6x + 2) + -40

Reorder the terms:
-36 + 12x = 2(2 + 6x) + -40
-36 + 12x = (2 * 2 + 6x * 2) + -40
-36 + 12x = (4 + 12x) + -40

Reorder the terms:
-36 + 12x = 4 + -40 + 12x

Combine like terms: 4 + -40 = -36
-36 + 12x = -36 + 12x

Add '36' to each side of the equation.
-36 + 36 + 12x = -36 + 36 + 12x

Combine like terms: -36 + 36 = 0
0 + 12x = -36 + 36 + 12x
12x = -36 + 36 + 12x

Combine like terms: -36 + 36 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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