12(x-3)=3(4x+4)-48

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Solution for 12(x-3)=3(4x+4)-48 equation: 



12(x-3)=3(4x+4)-48

We move all terms to the left:

12(x-3)-(3(4x+4)-48)=0

We multiply parentheses

12x-(3(4x+4)-48)-36=0



We calculate terms in parentheses: -(3(4x+4)-48), so:

3(4x+4)-48

We multiply parentheses

12x+12-48

We add all the numbers together, and all the variables

12x-36

Back to the equation:

-(12x-36)



We get rid of parentheses

12x-12x+36-36=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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