12(x-3)=4x+66+5x+36

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Solution for 12(x-3)=4x+66+5x+36 equation: 



12(x-3)=4x+66+5x+36

We move all terms to the left:

12(x-3)-(4x+66+5x+36)=0

We add all the numbers together, and all the variables

12(x-3)-(9x+102)=0

We multiply parentheses

12x-(9x+102)-36=0

We get rid of parentheses

12x-9x-102-36=0

We add all the numbers together, and all the variables

3x-138=0

We move all terms containing x to the left, all other terms to the right

3x=138

x=138/3

x=46

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