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12(x-3)=9x-20
We move all terms to the left:
12(x-3)-(9x-20)=0
We multiply parentheses
12x-(9x-20)-36=0
We get rid of parentheses
12x-9x+20-36=0
We add all the numbers together, and all the variables
3x-16=0
We move all terms containing x to the left, all other terms to the right
3x=16
x=16/3
x=5+1/3
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