12(x-4)=5(x-2)+3

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Solution for 12(x-4)=5(x-2)+3 equation: 



12(x-4)=5(x-2)+3

We move all terms to the left:

12(x-4)-(5(x-2)+3)=0

We multiply parentheses

12x-(5(x-2)+3)-48=0



We calculate terms in parentheses: -(5(x-2)+3), so:

5(x-2)+3

We multiply parentheses

5x-10+3

We add all the numbers together, and all the variables

5x-7

Back to the equation:

-(5x-7)



We get rid of parentheses

12x-5x+7-48=0

We add all the numbers together, and all the variables

7x-41=0

We move all terms containing x to the left, all other terms to the right

7x=41

x=41/7

x=5+6/7

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