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12(x-4)=6(x+1)
We move all terms to the left:
12(x-4)-(6(x+1))=0
We multiply parentheses
12x-(6(x+1))-48=0
We calculate terms in parentheses: -(6(x+1)), so:We get rid of parentheses
6(x+1)
We multiply parentheses
6x+6
Back to the equation:
-(6x+6)
12x-6x-6-48=0
We add all the numbers together, and all the variables
6x-54=0
We move all terms containing x to the left, all other terms to the right
6x=54
x=54/6
x=9
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