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12(x-5)-(7x-4)=x+3(2+4x-6)-5x
We move all terms to the left:
12(x-5)-(7x-4)-(x+3(2+4x-6)-5x)=0
We add all the numbers together, and all the variables
12(x-5)-(7x-4)-(x+3(4x-4)-5x)=0
We multiply parentheses
12x-(7x-4)-(x+3(4x-4)-5x)-60=0
We get rid of parentheses
12x-7x-(x+3(4x-4)-5x)+4-60=0
We calculate terms in parentheses: -(x+3(4x-4)-5x), so:We add all the numbers together, and all the variables
x+3(4x-4)-5x
We add all the numbers together, and all the variables
-4x+3(4x-4)
We multiply parentheses
-4x+12x-12
We add all the numbers together, and all the variables
8x-12
Back to the equation:
-(8x-12)
5x-(8x-12)-56=0
We get rid of parentheses
5x-8x+12-56=0
We add all the numbers together, and all the variables
-3x-44=0
We move all terms containing x to the left, all other terms to the right
-3x=44
x=44/-3
x=-14+2/3
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