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12(x-5)=3(2+4x)
We move all terms to the left:
12(x-5)-(3(2+4x))=0
We add all the numbers together, and all the variables
12(x-5)-(3(4x+2))=0
We multiply parentheses
12x-(3(4x+2))-60=0
We calculate terms in parentheses: -(3(4x+2)), so:We get rid of parentheses
3(4x+2)
We multiply parentheses
12x+6
Back to the equation:
-(12x+6)
12x-12x-6-60=0
We add all the numbers together, and all the variables
-66!=0
There is no solution for this equation
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