12(x-6)+20=4(3x-4)

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Solution for 12(x-6)+20=4(3x-4) equation:


Simplifying
12(x + -6) + 20 = 4(3x + -4)

Reorder the terms:
12(-6 + x) + 20 = 4(3x + -4)
(-6 * 12 + x * 12) + 20 = 4(3x + -4)
(-72 + 12x) + 20 = 4(3x + -4)

Reorder the terms:
-72 + 20 + 12x = 4(3x + -4)

Combine like terms: -72 + 20 = -52
-52 + 12x = 4(3x + -4)

Reorder the terms:
-52 + 12x = 4(-4 + 3x)
-52 + 12x = (-4 * 4 + 3x * 4)
-52 + 12x = (-16 + 12x)

Add '-12x' to each side of the equation.
-52 + 12x + -12x = -16 + 12x + -12x

Combine like terms: 12x + -12x = 0
-52 + 0 = -16 + 12x + -12x
-52 = -16 + 12x + -12x

Combine like terms: 12x + -12x = 0
-52 = -16 + 0
-52 = -16

Solving
-52 = -16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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