12(x=3)=3(4x+1)=33

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Solution for 12(x=3)=3(4x+1)=33 equation: 



12(x=3)=3(4x+1)=33

We move all terms to the left:

12(x-(3))=0

We multiply parentheses

12x-36=0

We move all terms containing x to the left, all other terms to the right

12x=36

x=36/12

x=3

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