12(y+1)+4=12(3y-2)-6

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Solution for 12(y+1)+4=12(3y-2)-6 equation: 



12(y+1)+4=12(3y-2)-6

We move all terms to the left:

12(y+1)+4-(12(3y-2)-6)=0

We multiply parentheses

12y-(12(3y-2)-6)+12+4=0



We calculate terms in parentheses: -(12(3y-2)-6), so:

12(3y-2)-6

We multiply parentheses

36y-24-6

We add all the numbers together, and all the variables

36y-30

Back to the equation:

-(36y-30)



We add all the numbers together, and all the variables

12y-(36y-30)+16=0

We get rid of parentheses

12y-36y+30+16=0

We add all the numbers together, and all the variables

-24y+46=0

We move all terms containing y to the left, all other terms to the right

-24y=-46

y=-46/-24

y=1+11/12

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