12(y+1)=4(4y+3)

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Solution for 12(y+1)=4(4y+3) equation: 



12(y+1)=4(4y+3)

We move all terms to the left:

12(y+1)-(4(4y+3))=0

We multiply parentheses

12y-(4(4y+3))+12=0



We calculate terms in parentheses: -(4(4y+3)), so:

4(4y+3)

We multiply parentheses

16y+12

Back to the equation:

-(16y+12)



We get rid of parentheses

12y-16y-12+12=0

We add all the numbers together, and all the variables

-4y=0

y=0/-4

y=0

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