12(y+1)=4(4y-3)

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Solution for 12(y+1)=4(4y-3) equation:



12(y+1)=4(4y-3)
We move all terms to the left:
12(y+1)-(4(4y-3))=0
We multiply parentheses
12y-(4(4y-3))+12=0
We calculate terms in parentheses: -(4(4y-3)), so:
4(4y-3)
We multiply parentheses
16y-12
Back to the equation:
-(16y-12)
We get rid of parentheses
12y-16y+12+12=0
We add all the numbers together, and all the variables
-4y+24=0
We move all terms containing y to the left, all other terms to the right
-4y=-24
y=-24/-4
y=+6

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