12(y+1)=4(y-11)-8

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Solution for 12(y+1)=4(y-11)-8 equation: 


Simplifying
12(y + 1) = 4(y + -11) + -8

Reorder the terms:
12(1 + y) = 4(y + -11) + -8
(1 * 12 + y * 12) = 4(y + -11) + -8
(12 + 12y) = 4(y + -11) + -8

Reorder the terms:
12 + 12y = 4(-11 + y) + -8
12 + 12y = (-11 * 4 + y * 4) + -8
12 + 12y = (-44 + 4y) + -8

Reorder the terms:
12 + 12y = -44 + -8 + 4y

Combine like terms: -44 + -8 = -52
12 + 12y = -52 + 4y

Solving
12 + 12y = -52 + 4y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-4y' to each side of the equation.
12 + 12y + -4y = -52 + 4y + -4y

Combine like terms: 12y + -4y = 8y
12 + 8y = -52 + 4y + -4y

Combine like terms: 4y + -4y = 0
12 + 8y = -52 + 0
12 + 8y = -52

Add '-12' to each side of the equation.
12 + -12 + 8y = -52 + -12

Combine like terms: 12 + -12 = 0
0 + 8y = -52 + -12
8y = -52 + -12

Combine like terms: -52 + -12 = -64
8y = -64

Divide each side by '8'.
y = -8

Simplifying
y = -8

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