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12(y+3)=5(2y-y)
We move all terms to the left:
12(y+3)-(5(2y-y))=0
We add all the numbers together, and all the variables
12(y+3)-(5(+y))=0
We multiply parentheses
12y-(5(+y))+36=0
We calculate terms in parentheses: -(5(+y)), so:We add all the numbers together, and all the variables
5(+y)
We multiply parentheses
5y
Back to the equation:
-(5y)
7y+36=0
We move all terms containing y to the left, all other terms to the right
7y=-36
y=-36/7
y=-5+1/7
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