12(y+4)=20y+32

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Solution for 12(y+4)=20y+32 equation: 



12(y+4)=20y+32

We move all terms to the left:

12(y+4)-(20y+32)=0

We multiply parentheses

12y-(20y+32)+48=0

We get rid of parentheses

12y-20y-32+48=0

We add all the numbers together, and all the variables

-8y+16=0

We move all terms containing y to the left, all other terms to the right

-8y=-16

y=-16/-8

y=+2

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