12(y+5)=7(2y+3)

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Solution for 12(y+5)=7(2y+3) equation: 



12(y+5)=7(2y+3)

We move all terms to the left:

12(y+5)-(7(2y+3))=0

We multiply parentheses

12y-(7(2y+3))+60=0



We calculate terms in parentheses: -(7(2y+3)), so:

7(2y+3)

We multiply parentheses

14y+21

Back to the equation:

-(14y+21)



We get rid of parentheses

12y-14y-21+60=0

We add all the numbers together, and all the variables

-2y+39=0

We move all terms containing y to the left, all other terms to the right

-2y=-39

y=-39/-2

y=19+1/2

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