12(y+7)+6=12(3y-1)-1

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Solution for 12(y+7)+6=12(3y-1)-1 equation: 



12(y+7)+6=12(3y-1)-1

We move all terms to the left:

12(y+7)+6-(12(3y-1)-1)=0

We multiply parentheses

12y-(12(3y-1)-1)+84+6=0



We calculate terms in parentheses: -(12(3y-1)-1), so:

12(3y-1)-1

We multiply parentheses

36y-12-1

We add all the numbers together, and all the variables

36y-13

Back to the equation:

-(36y-13)



We add all the numbers together, and all the variables

12y-(36y-13)+90=0

We get rid of parentheses

12y-36y+13+90=0

We add all the numbers together, and all the variables

-24y+103=0

We move all terms containing y to the left, all other terms to the right

-24y=-103

y=-103/-24

y=4+7/24

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