12(y-1)=-6(3+y)

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Solution for 12(y-1)=-6(3+y) equation: 



12(y-1)=-6(3+y)

We move all terms to the left:

12(y-1)-(-6(3+y))=0

We add all the numbers together, and all the variables

12(y-1)-(-6(y+3))=0

We multiply parentheses

12y-(-6(y+3))-12=0



We calculate terms in parentheses: -(-6(y+3)), so:

-6(y+3)

We multiply parentheses

-6y-18

Back to the equation:

-(-6y-18)



We get rid of parentheses

12y+6y+18-12=0

We add all the numbers together, and all the variables

18y+6=0

We move all terms containing y to the left, all other terms to the right

18y=-6

y=-6/18

y=-1/3

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